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    PDB 1ks4-3np2

Palladium Ionization Energy






The Palladium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Palladium.
Pd -> Pd+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Palladium is:
PdN+ -> Pd(N+1)+ + e-


Ionization Energy

Pd -> Pd1+ = 805 kJ/mol = 192.58 Kcal/mol
Pd1+ -> Pd2+ = 1875 kJ/mol = 448.56 Kcal/mol
Pd2+ -> Pd3+ = 3177 kJ/mol = 760.05 Kcal/mol
Pd3+ -> Pd4+ = 4700 kJ/mol = 1124.40 Kcal/mol
Pd4+ -> Pd5+ = 6300 kJ/mol = 1507.18 Kcal/mol
Pd5+ -> Pd6+ = 8700 kJ/mol = 2081.34 Kcal/mol
Pd6+ -> Pd7+ = 10700 kJ/mol = 2559.81 Kcal/mol
Pd7+ -> Pd8+ = 12700 kJ/mol = 3038.28 Kcal/mol
Pd8+ -> Pd9+ = 15000 kJ/mol = 3588.52 Kcal/mol
Pd9+ -> Pd10+ = 17200 kJ/mol = 4114.83 Kcal/mol
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