Palladium Ionization Energy

The Palladium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Palladium.
Pd -> Pd⁺ + e^-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Palladium is:
Pd^N+ -> Pd^(N+1)+ + e^-

Pd -> Pd¹⁺ = 805 kJ/mol = 192.58 Kcal/mol
Pd¹⁺ -> Pd²⁺ = 1875 kJ/mol = 448.56 Kcal/mol
Pd²⁺ -> Pd³⁺ = 3177 kJ/mol = 760.05 Kcal/mol
Pd³⁺ -> Pd⁴⁺ = 4700 kJ/mol = 1124.40 Kcal/mol
Pd⁴⁺ -> Pd⁵⁺ = 6300 kJ/mol = 1507.18 Kcal/mol
Pd⁵⁺ -> Pd⁶⁺ = 8700 kJ/mol = 2081.34 Kcal/mol
Pd⁶⁺ -> Pd⁷⁺ = 10700 kJ/mol = 2559.81 Kcal/mol
Pd⁷⁺ -> Pd⁸⁺ = 12700 kJ/mol = 3038.28 Kcal/mol
Pd⁸⁺ -> Pd⁹⁺ = 15000 kJ/mol = 3588.52 Kcal/mol
Pd⁹⁺ -> Pd¹⁰⁺ = 17200 kJ/mol = 4114.83 Kcal/mol